In an LCR circuit, the capacitance is made one-fourth, when in resonance. Then what should be the change in inductance, so that the circuit remains in resonance?

4 times

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(1/4) times

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8 times

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2 times

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Solution

The correct option is A 4 times
$a t r e s o n a n c e i n d u c t i v e r e a c t a n c e a n d c a p a c i t i v e r e a c t a n c e a r e e q u a l s o ω L = \frac{1}{ω C} \Rightarrow ω = \frac{1}{\sqrt{L C}} s o i f t h e c a p a c i t a n c e i s m a d e o n e - f o r t h, t h e n t h e i n d u c t a n c e m u s t b e f o u r t i m e s s o t h a t ω d o e s n^{'} t c h a n g e .$

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