In an LCR circuit, the potential difference between the terminals of the inductance is 60V, between the terminals of the capacitor is 30V and that across the resistance is 40V. Then, supply voltage will be:
A
50V
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B
70V
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C
130V
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D
10V
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Solution
The correct option is A50V Vz=√V2R+(VL−VC)2Vz=√(40)2+(60−30)2Vz=√1600+900Vz=50V