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Standard XII

Physics

Power Factor

In an LCR ser...

Question

In an LCR series circuit, $R = 200 Ω$ and the voltage and frequency of the main supply is 220V and 50 Hz respectively. On taking out the capacitance from the circuit, the current lags behind the voltage by $30^{\circ}$ . On taking out the inductor from the circuit, the current leads the voltage by $30^{\circ}$ . The power dissipated in the circuit is

305 W

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210 W

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zero

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242 W

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Solution

The correct option is D 242 W
As $ϕ = 30^{\circ}$ is same, $X_{L} = X_{C}$

$∴ P = \frac{V^{2}}{R} = 242 W$

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The correct option is D 242 WAs ϕ=30∘ is same, XL=XC ∴P=V2R=242W

The correct option is D 242 W
As $ϕ = 30^{\circ}$ is same, $X_{L} = X_{C}$

$∴ P = \frac{V^{2}}{R} = 242 W$