In an LCR series circuit, the rms voltages across R, L and C are found to be 10 V, 10 V and 20 V respectively. The rms voltage across the entire combination is

30 V

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μ

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20V

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10 \sqrt{2} V

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Solution

The correct option is C $10 \sqrt{2} V$
$V_{r m s} = \sqrt{V_{R}^{2} + (V_{L} - V_{C})^{2}}$
$= \sqrt{10^{2} + 10^{2}}$
$= 10 \sqrt{2} V$

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In an LCR series circuit, the rms voltages across R, L and C are found to be 10 V, 10 V and 20 V respectively. The rms voltage across the entire combination is

The correct option is C 10√2VVrms=√V2R+(VL−VC)2 =√102+102 =10√2V

The correct option is C $10 \sqrt{2} V$
$V_{r m s} = \sqrt{V_{R}^{2} + (V_{L} - V_{C})^{2}}$
$= \sqrt{10^{2} + 10^{2}}$
$= 10 \sqrt{2} V$