Question

In an n-p-n transistor circuit, the collector current is $9.9mA$. If 90% of the electrons emitted reach the collector, find out the value of emitter current.

• A. $1.1mA$
• B. $2.2mA$
• C. $9.9mA$
• D. $8.8mA$

Answer 1

The correct option is A $1.1mA$

x be the no. of electrons emitted per sec.

then $90$

$\frac{90}{100}\times x=9.9mA$

$\Rightarrow x=\frac{9.9mA\times 100}{90}$

$x=11mA$

$\therefore$ The value of emitter current $=11mA-9.9mA=1.1mA$