In an objective types paper of 150 questions:
John got $80 %$ correct answers and Mohan got $64 %$ correct answers. How many correct answers did each get?

John

= 96

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John

= 120

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Mohan

= 120

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Mohan

= 96

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Solution

The correct options are
A Mohan $= 96$
C John $= 120$
John got $\frac{80}{100} \times 150 = 120$ marks
Mohan got $\frac{64}{100} \times 150 = 96$ marks

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Similar questions

In an objective type paper of 150 questions; John got 80% correct answers and Mohan got 64% correct answers. (i) How many correct answers did each get ? (ii) What percent is Mohan's correct answers to John's correct answers ?

In an objective type paper of

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John got

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correct answers and Mohan got

64 %

correct answers.

What percent is Mohan's correct answers to John's correct answers?

Q. In an exam one Mark is awarded for one correct answers and 1\4 Marks is deducted for each wrong answers. A student who awarded a total of 120 questions, got 90 Mark. How many questions did he answer correctly

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Q. Question 21
In a competitive examination, 1 mark is awarded for each correct answer while

\frac{1}{2}

mark is deducted for every wrong answer. Jayanti answered 120 questions and got 90 marks. How many questions did she answer correctly?
Assume she answered all the questions.

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In an objective types paper of 150 questions: John got 80% correct answers and Mohan got 64% correct answers. How many correct answers did each get?

The correct options are A Mohan =96 C John =120John got 80100×150=120 marks Mohan got 64100×150=96 marks

In an objective types paper of 150 questions:
John got $80 %$ correct answers and Mohan got $64 %$ correct answers. How many correct answers did each get?

The correct options are
A Mohan $= 96$
C John $= 120$
John got $\frac{80}{100} \times 150 = 120$ marks
Mohan got $\frac{64}{100} \times 150 = 96$ marks