In an ordered set, half of them have values less than P and half of them have values greater than Q. Find the median of the set.

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P+Q

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\frac{P+Q}{2}

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Solution

The correct option is D $\frac{P+Q}{2}$
Let the no of elements in the set be 'x'.
Then the no of elements less than P and the no of elements greater than Q is x/2.
Here, x is even.
So, median is the average of the 2 middle elements.
Here, those 2 elements are P and Q.
So, median $= \frac{P+Q}{2}$

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In an ordered set, half of them have values less than P and half of them have values greater than Q. Find the median of the set.

The correct option is D P+Q2Let the no of elements in the set be 'x'. Then the no of elements less than P and the no of elements greater than Q is x/2. Here, x is even. So, median is the average of the 2 middle elements. Here, those 2 elements are P and Q. So, median =P+Q2

The correct option is D $\frac{P+Q}{2}$
Let the no of elements in the set be 'x'.
Then the no of elements less than P and the no of elements greater than Q is x/2.
Here, x is even.
So, median is the average of the 2 middle elements.
Here, those 2 elements are P and Q.
So, median $= \frac{P+Q}{2}$