In an organic compound, phosphorus is estimated
as______________.

M g_{2} P_{2} O_{7}

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H_{3} P O_{4}

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M g_{3} (P O_{4})_{2}

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P_{2} O_{5}

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Solution

The correct option is A $M g_{2} P_{2} O_{7}$
Estimation of Phosphorus
It is also estimated by Carius method. The organic compound containing phosphorus is heated with fuming nitric acid. Phosphorus is oxidised to phosphoric acid. It is precipitated as magnesium ammonium phosphate, $M g N H_{4} P O_{4}$ , by the addition of magnesia mixture $(M g S O_{4} + a q . N H_{3} + H_{4} C l)$ . The magnesium ammonium phosphate is washed, dried and ignited when it is converted to magnesium pyrophosphate $(M g_{2} P_{2} O_{7})$ .
$2 M g N H_{4} P O_{4} h e a t - - \to M g_{2} P_{2} O_{7} + 2 N H_{3} + H_{2} O$
From the mass of magnesium pyrophosphate, the percentage of phosphorus in the compound can be calculated.
Calculation: Mass of organic compound $= W g$
Mass of magnesium pyrophosphate $= W_{1} g$
$M g_{2} P_{2} O_{7} (222 g) \equiv 2 P (62 g)$

Percentage of $P = \frac{62}{222} \times \frac{W_{1}}{W} \times 100$

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