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Question

In an orthogonal cutting operation, cutting velocity is 40 m/min, shear angle 34 nd rake angle is 5, then the shear velocity is

A
45.6 m/min
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B
43.3 m/min
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C
41.8 m/min
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D
None
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Solution

The correct option is A 45.6 m/min
Vccos(ϕα)=Vfsinϕ=Vscosα

Vc=40 m/min, ϕ=34,α=5

Vs=Vccosαcos(ϕα)=40cos5cos(345)

Vs=45.56 m/min

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