Question

In an orthogonal cutting operation, cutting velocity is 40 m/min, shear angle ${34}^{\circ }$ nd rake angle is $5^{\circ }$, then the shear velocity is

• A. 45.6 m/min
• B. 43.3 m/min
• C. 41.8 m/min
• D. None

Answer 1

The correct option is A 45.6 m/min

$\frac{V_c}{\cos (\varphi -\alpha )}=\frac{V_f}{\sin \varphi }=\frac{V_s}{\cos \alpha }$

$V_c=40\text{m/min,}\varphi ={34}^{\circ },\alpha =5^{\circ }$

$V_s=\frac{V_c\cos \alpha }{\cos (\varphi -\alpha )}=\frac{40\cos 5^{\circ }}{\cos ({34}^{\circ }-5^{\circ })}$

$V_s=45.56\text{m/min}$