Question

In an orthogonal machining operation, the cutting and thrust forces are 600 N and 173 N respectively. If the value of shear angle is ${60}^{\circ }$, what is the approximate value of shear force?

• A. 100 N
• B. 150 N
• C. 200 N
• D. 300 N

Answer 1

The correct option is B 150 N

$F_s=F_c\cos \varphi -F_t\sin \varphi$

$=600\cos 60-173\sin 60$

$=600\times \frac{1}{2}-100\sqrt{3}\times \frac{\sqrt{3}}{2}[\because 173\approx 100\sqrt{3}]$

$=300-150$

$\Rightarrow F_s=150\text{N}$