Question

In an oxidation process for a cell,
$M_1\to M_1^{n+}+n{e}^{-}$
the other metal $\left(M_2\right)$ being univalent showing reduction takes up _____ electrons to complete redox reaction.

• A. $(n-1)$
• B. $1$
• C. $n$
• D. $2$

Answer 1

The correct option is C $n$

In a cell, the number of electrons released at anode is same as the number of electrons used at cathode.Thus

Given: Anode reaction is:

$M_1 \rightarrow M_{ 1}^{ n+ } + ne^-$

thus releases n electrons which will be taken up at cathode by $M_2^{1+}$ as its a univalent ion.

cathode reaction for n electrons is thus:

$n{M}_2^{1+}+n{e}^{-}\to n{M}_2$

the other metal ($M_2$) being univalent showing reduction takes up n electrons to complete the redox reaction.