Question

In an $\text{n-p-n}$ transistor circuit, the collector current is $10\text{mA}$. If $90\%$ of the electrons emitted from the emitter reach the collector, then the emitter current and base currents are

Answer 1

Given:

$I_C=10\text{mA}$ and

$\frac{90}{100}{I}_E=I_C$

$I_E=\frac{10}{0.9}mA=11.11\text{mA}$

$I_B=I_E-I_C=11.11-10=1.11\text{mA}$

Hence, Option $\left(C\right)$ is the correct answer.