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Question

In an trapezium ABCD, it is given that AB ∥ CD and AB = 2CD. Its diagonals AC and BD intersect at the point O such that ar(∆AOB) = 84 cm2. Find ar(∆COD).

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Solution

In ∆AOB and ∆COD, we have:



AOB = COD (Vertically opposite angles)OAB = OCD (Alternate angles as AB CD)Applying AA similiarity criterion, we get:AOB~COD ar(AOB )ar(COD) = AB2CD2 84ar(COD) = ABCD2 84ar(COD) = 2CDCD2 ar(COD) = 844 = 21 cm2

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