In an unbalanced three-phase system, phase current Ia = 1∠(−900) pu, negative sequence current Ib2 = 4∠(−1500) pu, zero sequence current Ic0 = 3∠900pu. The magnitude of phase current Ib in pu is
A
1.00
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B
7.81
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C
11.53
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D
13.00
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Solution
The correct option is C 11.53 Given, Ia = 1∠(−900) pu
Ib2 = 4∠(−1500) pu
Ic0 = 3 ∠(900)pu
As zero sequence current in all the three phases of unbalanced 3-ϕ system are equal, therefore,
Ia0 = Ib0 = Ic0 = 3∠900pu
Also, Ib2 = 4∠−1500
= Negative phase sequence current of phase b,
Therefore, referring to the negative phase sequence phasor,
Ia2 = 4∠(−1500−1200)=4∠−2700 pu
We know that, phase current vectors in matrix form are given by