In an X-Ray tube the current is 1 mA. The number of electrons striking the target per second is (given e $= 1.6 \times 10^{- 19}$ C):

6.25 \times 10^{18}

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6.25 \times 10^{16}

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6.25 \times 10^{15}

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6.25 \times 10^{14}

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Solution

The correct option is C $6.25 \times 10^{15}$

$c u r r e n t = \frac{q}{t}$
$q = c u r r e n t \times t$
$= 1 \times 10^{- 3} C$
$= 10^{- 3} C$
$q = n e$
$s o, n = \frac{q}{e}$
$= \frac{10^{- 3} C}{1.6 \times 10^{- 19} C}$
$= 6.25 \times 10^{15}$

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In an X-Ray tube the current is 1 mA. The number of electrons striking the target per second is (given e =1.6×10−19 C):

The correct option is C 6.25×1015 current= qtq= current×t= 1×10−3C=10−3Cq=n eso, n=qe=10−3C1.6×10−19C= 6.25×1015

In an X-Ray tube the current is 1 mA. The number of electrons striking the target per second is (given e $= 1.6 \times 10^{- 19}$ C):

The correct option is C $6.25 \times 10^{15}$

$c u r r e n t = \frac{q}{t}$
$q = c u r r e n t \times t$
$= 1 \times 10^{- 3} C$
$= 10^{- 3} C$
$q = n e$
$s o, n = \frac{q}{e}$
$= \frac{10^{- 3} C}{1.6 \times 10^{- 19} C}$
$= 6.25 \times 10^{15}$