In aniline, the lone pair of electrons on the $N$ atom is delocalised over the benzene ring. As a result, the electron density on nitrogen increases.

True

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False

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Solution

The correct option is B False
In aniline, the lone pair of electrons on the $N$ atom is delocalised over the benzene ring. As a result, the electron density on nitrogen decreases.

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Similar questions

Q. Assertion :

p K b

of aniline is more than that of methylamine. Reason: In aniline, the lone pair of electrons on the

N

atom is delocalized over the benzene ring. As a result, the electron density of nitrogen decreases. In contrast, in

{C H}_{3} {N H}_{2} (+ I)

effect of

{C H}_{3}

increases the electron density on the

N

atom. Therefore, aniline is a weaker base than methylamine and hence its

p K_{b}

value is higher than that of methylamine.

Q. Given below are two statements

Statement I : Aniline is less basic than acetamide.
Statement II: In aniline, the lone pair of electrons on nitrogen atom is delocalise over benzene ring due to resonance and hence less available to a proton.

Choose the most appropriate option

A : Nitration of aniline can only be done by protecting $- N H_{2}$ group through acetylation.
R : Acetylation of aniline results in the increase of electron density at the benzene ring.

Q. In

N O_{3}^{-}

ion, number of bond pair and lone pair of electron on nitrogen atom are:

Q. In

{N O_{3}}^{-}

ion, find the sum of bond pairs and lone pairs of electrons on nitrogen atom.

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In aniline, the lone pair of electrons on the N atom is delocalised over the benzene ring. As a result, the electron density on nitrogen increases.

The correct option is B FalseIn aniline, the lone pair of electrons on the N atom is delocalised over the benzene ring. As a result, the electron density on nitrogen decreases.

In aniline, the lone pair of electrons on the $N$ atom is delocalised over the benzene ring. As a result, the electron density on nitrogen increases.

The correct option is B False
In aniline, the lone pair of electrons on the $N$ atom is delocalised over the benzene ring. As a result, the electron density on nitrogen decreases.