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Question

In any ΔABC, 2[asin2(C2)+csin2(A2)] equals

A
a+cb
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B
ac+b
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C
a+c+b
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D
acb
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Solution

The correct option is A a+cb
2[asin2(C2)+csin2(A2)]
=[a(1cosC)+c(1cosA)]
=a+c(acosC+ccosA)
=a+cb [By projection formulae]

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