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Question

In any ΔABC,1r1+1r2+1r3 is equal to


A

3/r

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B

1/r

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C

2/r

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D

1

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Solution

The correct option is B

1/r


We have, 1r1+1r2+1r3=saΔ+sbΔ+scΔ=3s(a+b+c)Δ=3s2sΔ=sΔ=1r


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