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Question

In any ΔABC, the least value of (sin2A+sin A+1sin A) is

A
3
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B
3
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C
9
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D
None of these
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Solution

The correct option is A 3
sin2A+sin A+1sin A=sin A+1sin A+1
=[(sin A1sin A)2+3]3
Hence (A) is the correct answer

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