In any - ABC- the least value of sin2-A-sin- A-1-sin A is

Sin^2A+sin A+1/sin A=sin A+1/sin A+1 = [ ( √(sin A) 1/√(sin A) ) ^2+3 ]⩾ 3 Hence (A) is the correct answer ...

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Trigonometric Ratios Using Right Angled Triangle

In any Δ ABC,...

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In any $Δ A B C$ , the least value of $(\frac{s i n^{2} A + s i n A + 1}{s i n A})$ is

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\sqrt{3}

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None of these

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