In any ΔABC where ∠ B=90 ∘, sin2A + cos2C = 1.
Given that, sin2A + cos2C=1
But, we know that sin2C + cos2C =1
∴if sin2A+cos2C=1, then ∠A=∠C But, ∠A=∠C only if △ABC is isosceles.
Therefore, the above statement is not always true.
In any ΔABC where ∠B=90∘, sin2A+cos2C=1
State True or False
In any △ABC where ∠B=90∘, then sin2A+cos2C=1