In any right angled triangle ABC- right angle at - A- If AB - 100-3- AC - 100- Find angle C-

The correct option is B 60^∘ It is given that AB=100√(3) and AC=100 such that ∠ A=90^0 .Therefore, BC is the hypotenuse.Now ta ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Standard Values of Trigonometric Ratios

In any right ...

Question

In any right angled triangle $A B C$ , right angle at $∠ A$ . If $A B = 100 \sqrt{3}, A C = 100$ . Find angle $C$ .

30^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60^{\circ}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

45^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

120^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $60^{\circ}$
It is given that $A B = 100 \sqrt{3}$ and $A C = 100$ such that $∠ A = 90^{0}$ .

Therefore, $B C$ is the hypotenuse.

Now $tan ∠ C = \frac{A B}{A C} = \frac{100 \sqrt{3}}{100} = \sqrt{3}$ .

Thus $tan C = \sqrt{3} = tan 60^{0}$ .

Hence $∠ C = 60^{0}$ .

Suggest Corrections

Similar questions

Q. In

△ A B C, A B = A C

and

∠ A = 100^{o}

find

∠ C

In the figure, triangle ABC is an isosceles triangle with AB = AC and measure of angle ABC = 50^o. Then the measure of angle BDC and angle BEC will be

Q. In

△

ABC,

∠

A=100

^{o}

and AB = AC. Find

∠

B and

∠

In a triangle ABC, right angled at A, AB = AC. Find the value of angle B and angle C.

Q. In a right angle triangle ABC right angled at B, if AB = 4 cm, BC = 3 cm, then AC =

Join BYJU'S Learning Program

In any right angled triangle ABC, right angle at ∠A. If AB=100√3,AC=100. Find angle C.

The correct option is B 60∘It is given that AB=100√3 and AC=100 such that ∠A=900.Therefore, BC is the hypotenuse.Now tan∠C=ABAC=100√3100=√3.Thus tanC=√3=tan600.Hence ∠C=600.

In any right angled triangle $A B C$ , right angle at $∠ A$ . If $A B = 100 \sqrt{3}, A C = 100$ . Find angle $C$ .

The correct option is B $60^{\circ}$
It is given that $A B = 100 \sqrt{3}$ and $A C = 100$ such that $∠ A = 90^{0}$ .

Therefore, $B C$ is the hypotenuse.

Now $tan ∠ C = \frac{A B}{A C} = \frac{100 \sqrt{3}}{100} = \sqrt{3}$ .

Thus $tan C = \sqrt{3} = tan 60^{0}$ .

Hence $∠ C = 60^{0}$ .