Question

In any transition series, as we move from left to right the $d$-orbitals are progressively filled and their properties vary accordingly.

Which of the following is the correct order of second ionization energy?

• A. $V>Cr>Mn$
• B. $V<Cr=Mn$
• C. $V<Mn<Cr$
• D. $V>Cr<Mn$

Answer 1

The correct option is C

$V<Mn<Cr$

Ionization from $C{r}^{+}$ is unusually high because ionization occurs from a half-filled d subshell while ionization from Mn+ is a bit low because the product ion $M{n}^{2+}$ is half-filled.