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Question

In any triangle ABC A2,B2,C2 are in QP prove that cotA,cotB,cotC,are in A.P

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Solution

Let us consider that cotA,cotB,cotC are in AP and prove that a2,b2,c2 are in AP.
we know that cotA=\frac{b^{2}+c^{2}-a^{2}}{4(area of triangle)} and similarly cotB,cotC..
by considering that cotA,cotB,cotC are inAP,we get
2(c2+a2-b2)=(b2+c2-a2)+(b2+a2-c2),
by simplifying,we get
2b2=a2+c2,
\thereforea2,b2,c2 are in AP

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