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Question

In any ABC, prove that: cosAa+cosBb+cosCc=a2+b2+c22abc.

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Solution

cosAa+cosBb+cosCc
=b2+c2a22bc×a+c2+a2b22ca×b+a2+b2c22ab×c (Using cosine rule)

=b2+c2a2+c2+a2b2+a2+b2c22abc=a2+b2+c22abc

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