CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In any ABC, prove that: cosAa+cosBb+cosCc=a2+b2+c22abc.

Open in App
Solution

cosAa+cosBb+cosCc
=b2+c2a22bc×a+c2+a2b22ca×b+a2+b2c22ab×c (Using cosine rule)

=b2+c2a2+c2+a2b2+a2+b2c22abc=a2+b2+c22abc

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon