Question

In any $△ABC$, the least value of $\left(\frac{si{n}^{2}A+sinA+1}{sinA}\right)$ is

• A. 3
• B.
• C. 9
• D. None of these

Answer 1

The correct option is A

3

$\left(\frac{si{n}^{2}A+sinA+1}{sinA}\right)=sinA+\frac{1}{sinA}+1$
$\left[\right(\sqrt{sinA}-\frac{1}{\sqrt{sinA}}{)}^2+3]>3$
Hence(A).