In any triangle ABC- the simplified form of cos 2A a2 - cos 2 Bb2 is -

The correct option is C 1a^2 1b^2 ...

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Equal Angles Subtend Equal Sides

In any triang...

Question

In any triangle $A B C,$ the simplified form of $\frac{cos 2 A}{a^{2}} - \frac{cos 2 B}{b^{2}}$ is :

a^{2} - b^{2}

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\frac{1}{a^{2} - b^{2}}

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\frac{1}{a^{2}} - \frac{1}{b^{2}}

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a^{2} + b^{2}

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Solution

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△ A B C

\frac{cos 2 A}{a^{2}} - \frac{cos 2 B}{b^{2}} = (\frac{1}{a^{2}} - \frac{1}{b^{2}})

$\frac{c o s 2 A}{a^{2}} - \frac{c o s 2 B}{b^{2}} = \frac{1}{a^{2}} - \frac{1}{b^{2}}$

\frac{cos 2 A}{a^{2}} - \frac{cos 2 B}{b^{2}} = (\frac{1}{a^{2}} - \frac{1}{b^{2}})

(a^{2} b^{2} c^{3} - a^{2} b^{2} c^{3} + a^{2} b^{2} c^{3}) \div a^{2} b^{2} c^{3}

\frac{a + \sqrt{a^{2} - b^{2}}}{a - \sqrt{a^{2} - b^{2}}} + \frac{a - \sqrt{a^{2} - b^{2}}}{a + \sqrt{a^{2} - b^{2}}}

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