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Frankland Halide Reaction

In aqueous al...

Question

In aqueous alkaline solution, two electrons reduction of ${H O_{2}}^{-}$ gives :

H O^{-}

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H_{2} O

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O_{2}

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O_{2}^{-}

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Solution

The correct option is A $H O^{-}$
In aqueous alkaline solution, two electrons reduction of $H O_{2}^{-}$ gives $H O^{-}$ .

${H O_{2}}^{-} + H_{2} O + 2 e^{-} \to {3 O H}^{-}$

Hence, option $A$ is correct.

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