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Standard XII

Chemistry

Standard Electrode Potentials

In aqueous so...

Question

In aqueous solution, $H_{2}$ will not reduce:

F e^{3 +}

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C u^{2 +}

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A g^{+}

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Z n^{2 +}

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Solution

The correct option is D $Z n^{2 +}$
According to standard electrode, apart form $Z n^{+ 2}$ all other ion have higher reduction potential than $H^{+}$ so, they can be reduced by $H_{2}$ but as $Z n^{+ 2}$ has lower reduction potential than $H^{+}$ so it can not be reduced by $H_{2}$ .

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Similar questions

Q. An aqueous solution which is slightly acidic contain cations

F e^{3 +}

Z n^{2 +}

and

C u^{2 +}

. The reagent that when added in excess to this solution would identify the separate

F e^{3 +}

ion in one step is_________.

The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +}$ and $C u^{2 +}$ . The reagent that when added in excess of this solution would identify and separate $F e^{3 +}$ in one step is:

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

Q. What is the number of pairs of ions which are coloured in aqueous solutions ?
(i)

T i^{3 +}, V^{3 +}

(ii)

C u^{+}, S c^{3 +}

(iii)

F e^{2 +}, F e^{3 +}

(iv)

C o^{2} +, N i^{2 +}

(v)

Z n^{2 +}, A g^{+}

Q. The only cations present in a slightiy acidic solution are

F e^{3 +}

Z n^{2 +}

and

C u^{2 +}

The reagent that when added in excess to this solution would identify and separate

F e^{3 +}

in one step is :

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In aqueous solution, H2 will not reduce:

The correct option is D Zn2+According to standard electrode, apart form Zn+2 all other ion have higher reduction potential than H+ so, they can be reduced by H2 but as Zn+2 has lower reduction potential than H+ so it can not be reduced by H2.

In aqueous solution, $H_{2}$ will not reduce:

The correct option is D $Z n^{2 +}$
According to standard electrode, apart form $Z n^{+ 2}$ all other ion have higher reduction potential than $H^{+}$ so, they can be reduced by $H_{2}$ but as $Z n^{+ 2}$ has lower reduction potential than $H^{+}$ so it can not be reduced by $H_{2}$ .