In aqueous solution, ${[C o {(H_{2} O)}_{6}]}^{2 +}$ $(X)$ reacts with molecular oxygen in the presence of excess liquor $N H_{3}$ to give a new complex $Y$ . The number of unpaired electrons in $X$ and $Y$ are, respectively.

3, 1

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3, 0

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3, 3

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7, 0

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Solution

The correct option is D $3, 0$
${[C o {(H_{2} O)}_{6}]}^{2 +}$ has $C o^{2 +}$ ion with $3 d^{7}$ outer electronic configuration and has 3 unpaired electrons as it is high spin or spin free complex.
It reacts with molecular oxygen in the presence of excess liquor $N H_{3}$ to give a new complex $Y,$ ${[C o {(N H_{3})}_{6}]}^{3 +}$ . It has $C o^{3 +}$ ion with $3 d^{6}$ outer electronic configuration and has 0 unpaired electrons as it is low spin or spin paired complex.

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In aqueous solution, [Co(H2O)6]2+ (X) reacts with molecular oxygen in the presence of excess liquor NH3 to give a new complex Y. The number of unpaired electrons in X and Y are, respectively.

In aqueous solution, ${[C o {(H_{2} O)}_{6}]}^{2 +}$ $(X)$ reacts with molecular oxygen in the presence of excess liquor $N H_{3}$ to give a new complex $Y$ . The number of unpaired electrons in $X$ and $Y$ are, respectively.