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Question

In Arrhenius equation for a certain reaction, the values of A and Ea (activation energy) are 4×1013 sec1 and 98.6 kJ mol1 respectively. At what temperature, the reaction will have specific rate constant 1.1×103 sec1?

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Solution

According to Arrhenius equation,
k=AeEa/RT
or logek=logeAEaRTlogee
or 2.303log10k=2.303log10AEaRT
or 2.303log(1.1×103)=2.303log(4×1013)98.6×1038.314×T
T=98.6×1038.314×2.303×16.56K=310.96K

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