In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of 3.15 × 10–18 J from the radiations of 600 nm, calculate the number of photons received by the detector.
From the expression of energy of one photon (E),
E=hcλ
Where, λ = wavelength of radiation
h = Planck’s constant
c = velocity of radiation
Substituting the values in the given expression of E:
E=(6.626×10−34Js)(3×108ms−1)(600×10−9m)=3.313×10−19J
Energy of one photon = 3.313 × 10–19 J
Number of photons received with 3.15 × 10–18 J energy
3.15×10−18J3.313×10−19J=9.5≈10