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Standard XII

Chemistry

Planck's Quantum Hypothesis

In astronomic...

Question

In astronomical observations signals observed from the distant stars are generally weak. If the photon detector receives a total of $3.15 \times 10^{- 18}$ J from the radiations of $600$ nm. Calculate the number of photons received by the detector.

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Solution

The correct option is C 10
Energy of one photon $= h ν$
$= \frac{h c}{λ}$
$E = \frac{(6.626 \times 10^{34}) (3 \times 10^{8})}{600 \times 10^{- 9}}$
$= 3.313 \times 10^{- 19} J$
Total energy received is $3.15 \times 10^{18 J}$
Hence ,
Number of photon received $= \frac{3.15 \times 10^{- 18}}{3.313 \times 10^{- 19}}$
$= 9.51 \approx 10$

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In astronomical observations signals observed from the distant stars are generally weak. If the photon detector receives a total of 3.15×10−18 J from the radiations of 600 nm. Calculate the number of photons received by the detector.

The correct option is C 10Energy of one photon =hν=hcλE=(6.626×1034)(3×108)600×10−9=3.313×10−19JTotal energy received is 3.15×1018J Hence ,Number of photon received=3.15×10−183.313×10−19 =9.51≈10

In astronomical observations signals observed from the distant stars are generally weak. If the photon detector receives a total of $3.15 \times 10^{- 18}$ J from the radiations of $600$ nm. Calculate the number of photons received by the detector.