In Atwood's machine, two masses $3 k g$ and $5 k g$ are connected by a light string which passes over a frictionless pulley. The support of the pulley is attached to the ceiling of a compartment of a train. If the train moves in a horizontal direction with a constant acceleration $8 m s^{- 2}$ , the tension in the string in $N$ is $(g = 10 m s^{- 2})$ :

3.75

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37.5

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15

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20

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Solution

The correct option is D $37.5$
$50 - T_{1} = 5 a$
$T_{1} - 30 = 3 a$
$T_{1} = 37.5$
it is not depends on horizontal acceleration.
Correct option is (B).

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The correct option is D 37.550−T1=5aT1−30=3aT1=37.5it is not depends on horizontal acceleration.Correct option is (B).

The correct option is D $37.5$
$50 - T_{1} = 5 a$
$T_{1} - 30 = 3 a$
$T_{1} = 37.5$
it is not depends on horizontal acceleration.
Correct option is (B).