Question

In the given figure, $ \angle B<\angle A$ and $ \angle C<\angle D$. Show that $ AD.

Answer 1

Prove that $AD<BC$.

Since it is given that $\angle B<\angle A$.

Therefore, $OA<OB...1$ {Opposite side of the greater angle will be greater}

Similarly, $\angle C<\angle D$

Therefore, $OD<OC...2$ {Opposite side of the greater angle will be greater}

Add equation $1$ and equation $2$.

$OA+OD<OB+OC$

Since, $OA+OD=AD$ and $OB+OC=BC$.

Therefore, $AD<BC$.

Hence prove, $AD<BC$.