In balanced metre bridge- the resistance of bridge wire is 0-1 -cm- Unknown resistance -X- is connected in left gap and 6 - in right gap- null point divides the wire in the ratio 2 - 3- Find the current drawn from the battery of 5V having negligible resistance-

The correct option is B 1 AResistance of meter bridge = 100× 0.1=10Ω x6=23→ x=4Ω 1R_t=16+4+110→ R_T=5 I=VR_T=55=1A ...

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Standard XII

Physics

Wheatstone Bridge

In balanced m...

Question

In balanced metre bridge, the resistance of bridge wire is 0.1 $Ω$ /cm. Unknown resistance 'X' is connected in left gap and 6 $Ω$ in right gap, null point divides the wire in the ratio 2 : 3. Find the current drawn from the battery of 5V having negligible resistance.

1 A

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1.5 A

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2 A

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5 A

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Solution

The correct option is B 1 A
Resistance of meter bridge = $100 \times 0.1 = 10 Ω$
$\frac{x}{6} = \frac{2}{3} \to x = 4 Ω$
$\frac{1}{R_{t}} = \frac{1}{6 + 4} + \frac{1}{10} \to R_{T} = 5$
$I = \frac{V}{R_{T}} = \frac{5}{5} = 1 A$

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In balanced metre bridge, the resistance of bridge wire is 0.1 Ω/cm. Unknown resistance 'X' is connected in left gap and 6Ω in right gap, null point divides the wire in the ratio 2 : 3. Find the current drawn from the battery of 5V having negligible resistance.

The correct option is B 1 AResistance of meter bridge =100×0.1=10Ωx6=23→x=4Ω1Rt=16+4+110→RT=5I=VRT=55=1A

In balanced metre bridge, the resistance of bridge wire is 0.1 $Ω$ /cm. Unknown resistance 'X' is connected in left gap and 6 $Ω$ in right gap, null point divides the wire in the ratio 2 : 3. Find the current drawn from the battery of 5V having negligible resistance.

The correct option is B 1 A
Resistance of meter bridge = $100 \times 0.1 = 10 Ω$
$\frac{x}{6} = \frac{2}{3} \to x = 4 Ω$
$\frac{1}{R_{t}} = \frac{1}{6 + 4} + \frac{1}{10} \to R_{T} = 5$
$I = \frac{V}{R_{T}} = \frac{5}{5} = 1 A$