In balancing the reaction XZn-NO-3 - YH- - XZn2- - NH-4 - ZH2O- X- Y and Z are-

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Balancing Chemical Equations by Partial Equation Method

In balancing ...

Question

In balancing the reaction $X Z n + N O_{3}^{-} + Y H^{+} \to X Z n^{2 +} + N H_{4}^{+} + Z H_{2} O$ , $X, Y$ and $Z$ are:

4, 10, 3

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3, 8, 3

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3, 10, 3

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4, 3, 10

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Solution

The correct option is A 4, 10, 3
$X Z n + N O_{3}^{-} + Y H^{+} ⟶ X Z n^{2 +} + N H_{4}^{+} + Z H_{2} O$
or,
$4 Z n + N O_{3}^{-} + 10 H^{+} ⟶ 4 Z n^{2 +} + N H_{4}^{+} + 3 H_{2} O$
$Z n = 4$ $Z n = 4$
$N = 1$ $N = 1$
$O = 3$ $O = 3$
$H = 10$ $H = 6 + 4$

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In balancing the reaction XZn+NO−3+YH+→XZn2++NH+4+ZH2O, X, Y and Z are:

The correct option is A 4, 10, 3XZn+NO−3+YH+⟶XZn2++NH+4+ZH2Oor,4Zn+NO−3+10H+⟶4Zn2++NH+4+3H2O Zn=4 Zn=4 N=1 N=1 O=3 O=3 H=10 H=6+4

In balancing the reaction $X Z n + N O_{3}^{-} + Y H^{+} \to X Z n^{2 +} + N H_{4}^{+} + Z H_{2} O$ , $X, Y$ and $Z$ are:

The correct option is A 4, 10, 3
$X Z n + N O_{3}^{-} + Y H^{+} ⟶ X Z n^{2 +} + N H_{4}^{+} + Z H_{2} O$
or,
$4 Z n + N O_{3}^{-} + 10 H^{+} ⟶ 4 Z n^{2 +} + N H_{4}^{+} + 3 H_{2} O$
$Z n = 4$ $Z n = 4$
$N = 1$ $N = 1$
$O = 3$ $O = 3$
$H = 10$ $H = 6 + 4$