In Ballmer series of line of hydrogen spectrum the third line from red end corresponds to which inner orbit jump of electron for Bohr orbit in hydrogen atom.

I have got the solution of this question earlier too but I could not understand the solution .please give the solution in a little more explanative and detailed manner.

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Solution

Since the line in hydrogen spectrum lies within visible region that is at red end, therefore it is corresponds to the Balmer series.
The line at the red end suggests that
The first line of Balmer series is n = 3 to n =2
The second line of Balmer series is n = 4 to n = 2
The third line of Balmer series is n = 5 to n = 2

Thus answer is (2)
5 → 2
I hope u got it

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