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Question

In below shown figure, PSSQ= PTTR andPST= PRQ. Then ΔPQR is a/an __ triangle.


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Solution

It is given that

PSSQ = PTTR

So, ST||QR [By converse of Basic Proportionality Theorem]

, PST=PQR (Corresponding Angles)

Also, it is given that

PST = PRQ

So,PRQ = PQR

Therefore, PQ = PR (Sides opposite the equal angles)

i.e., ΔPQR is an isosceles triangle.


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