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Question

In BF3, the B - F bond length is 1.30 A. When BF3 is allowed to react with Me3N, it forms an adduct, Me3NBF3. The bond length of B - F in the adduct is:

A
greater than 1.30A
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B
smaller than 1.30A
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C
equal to 1.30A
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D
none of these
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Solution

The correct option is A greater than 1.30A
In BF3, there is back bonding in between fluorinc and boron due to presence of p-orbital in boron. back bonding imparts double bond characteristics. As BF3 forms adjuct the back bonding is no longer present and thus double bond characteristic disappears. Hence, bond becomes a bit longer than earlier ( 1.30 A0).
1317425_769309_ans_41f665f428fe490dba79a00dccf29e93.PNG

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