In BF3, the B - F bond length is 1.30 A. When BF3 is allowed to react with Me3N, it forms an adduct, Me3N→BF3. The bond length of B - F in the adduct is:
A
greater than 1.30A
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B
smaller than 1.30A
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C
equal to 1.30A
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D
none of these
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Solution
The correct option is A greater than 1.30A In BF3, there is back bonding in between fluorinc and boron due to presence of p-orbital in boron. back bonding imparts double bond characteristics. As BF3 forms adjuct the back bonding is no longer present and thus double bond characteristic disappears. Hence, bond becomes a bit longer than earlier ( 1.30 A0).