In $△$ ABC, $∠ A : ∠ B : ∠ C = 1 : 2 : 3$ Find BC : AB.

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Solution

For any triangle the ratio of angles is in proportion to their opposite sides.
Hence, $∠ A : ∠ B : ∠ C = B C : A C : A B$
or, $∠ A : ∠ B = B C : A B$
$B C : A B = 1 : 2$

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In a ΔABC, AB = BC and ∠B = 64°. Find ∠C.

$\frac{x}{a} + \frac{x}{b} + \frac{x}{c} = 1. F i n d t h e v a l u e o f x .$

△ A B C, A B = B C

∠ B = 64^{o}

∠ C

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