Question

In $△$ABC, X, Y and Z are the mid-points of side AB, side BC and side AC respectively.
AB = 5cm, AC = 9cm and BC = 11cm, then find XY.

• A. $2.5cm$
• B. $3.2cm$
• C. $4.2cm$
• D. $4.5cm$

Answer 1

The correct option is D $4.5cm$

According to the midpoint theorem, the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side.

So, In $△ABC$, $X$ and $Y$ are the midpoints of $AB$ and $BC$, then $XY$ is half of $AC$.

$\therefore XY=\frac{AC}{2}=\frac{9}{2}=4.5cm$