Question

In $△$ABC, X, Y, and Z are the mid-points of side AB, side BC and side AC respectively.
AB = 5cm, AC = 9cm and BC = 11cm, then find XZ.

• A. 2.7 cm
• B. 5.5 cm
• C. 8.3 cm
• D. 9.5 cm

Answer 1

Answer: (B)

5.5 cm

According to the midpoint theorem, the line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side.

So, In $△ABC$, $X$ and $Z$ are the midpoints of $AB$ and $AC$, then $XZ$ is half of $BC$.

$\therefore XZ=\frac{BC}{2}=\frac{11}{2}=5.5cm$