Question

In Bohr atom model for Hydrogen, which of the following transition will result in a photon of smallest wavelength ?

• A. $n=5$ to $n=4$
• B. $n=6$ to $n=5$
• C. $n=2$ to $n=1$
• D. $n=3$ to $n=2$

Answer 1

The correct option is C $n=2$ to $n=1$

Energy released $△E=\frac{hc}{\lambda }$
$\Rightarrow$ Wavelength of emitted radiation,
$\lambda \propto \frac{1}{△E}$.

For shorter wavelength $△E$ has to be maximum.

$△E$ is maximum for transition $n=2$ to $n=1$