Question

In Bohr atomic model an electron is revolving round the nucleus in a circular path of radius $5.1\times {10}^{-11}$$m$ with a frequency $6.8\times {10}^{15}$cycles/sec. The magnetic induction at the center of the orbit will be :
(Given charge on electron $e=1.6\times {10}^{-19}C$)

• A. 11.6 Tesla
• B. 13.4 Tesla
• C. 15.6 Tesla
• D. 14.6 Tesla

Answer 1

The correct option is B 13.4 Tesla

$B=\frac{{\mu }_{0}i}{2r}$

$i=\frac{q}{T}=q\times f$, where $T$ is time period and $f$ is the frequency

=$\frac{{\mu }_{0}qf}{2r}$

=$\frac{4\pi \times {10}^{-7}\times 1.6\times {10}^{-19}\times 6.8\times {10}^{15}}{2\times 5.1\times {10}^{-11}}$

=$13.4Tesla$