Question

In Bohr's model of hydrogen atom, let $\text{PE}$ represent, the potential energy and $\text{TE}$ represent the total energy. In going from lower to a higher orbit.

• A. $\text{PE}$ decreases ; $\text{TE}$ decreases
• B. $\text{PE}$ increases ; $\text{TE}$ increases
• C. $\text{PE}$ decreases ; $\text{TE}$ increases
• D. $\text{PE}$ increases ; $\text{TE}$ decreases

Answer 1

The correct option is B $\text{PE}$ increases ; $\text{TE}$ increases

For, Hydrogen like atoms, the ratio of $\text{P.E}$ to the $\text{T.E}$ is,

$\frac{\text{P.E}}{\text{T.E}}=\frac{2}{1}$

$\because \text{T.E}=-13.6\frac{Z^2}{n^2}$

In going from lower to a higher orbit, both $\text{P.E}$ and $\text{T.E}$ increases.

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(B\right)$ is the correct answer.