In Bohr's model of hydrogen atom, radius of the first orbit of an electron is r0. Then, radius of the third orbit is?
A
r09
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B
r0
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C
3r0
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D
9r0
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Solution
The correct option is C9r0 Radius of the nth orbit of an electron is given by rn=ron2Z For hydrogen atom, Z=1 ⟹rn=ron2 So, for third orbit n=3 Thus radius of third orbit r3=ro×32=9ro