In bohr series of lines of hydrogen spectrum the third line from the red end corresponds to which inter Orbit jumps of the electron for bohr Orbit in an atom of Hydrogen

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Solution

Since the line in hydrogen spectrum lies within visible region that is at red end, therefore it is corresponds to the Balmer series.
The line at the red end suggests that
The first line of Balmer series is n = 3 to n =2
The second line of Balmer series is n = 4 to n = 2
The third line of Balmer series is n = 5 to n = 2
So answer is
5 → 2

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